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04/13/2012

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Given the following:

mi = 50 - Mass of ice (gm)
ti = 0 - Ice temperature (deg C)
ms = 10 - Mass of steam (gm)
ts = 100 - Steam temperature (deg C))

Using the following constants:

ci = 2100 - Ice thermal capacity (J/kg*deg)
l = 3.4*10^5 - Ice fusion heat (J/kg)
cw = 4100 - Water thermal capacity (J/kg*deg)
r = 2.2*10^6 - Steam condensing heat (J/kg)

Solution:

First of all, we need to figure out what will be inside at the end - just the ice,
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